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# Média e variação de uma variável aleatória binomial

• Nota de Estudos
• Rever Tópicos
 Torben Mark O. 0 0 In solution 12 there is a mistake and I don't know if I'm right with my idea in terms of corrrection of this mistake. If X~Bi(12, 0.74) then Var(X)=12 x 0,74 x 0,25 = 2,22 and stdev(X)=√2,22=(2,22)^(0,5)=1,4899664426≈1,49(≈1,5 ?). In the modul there is follwing calculcation: If X~Bi(12, 0.74) then Var(X)=12 x 0,75 x 0,25 = 2,22 ... =>X~Bi(n;p)=> n=12 and p=0,74 => X~Bi(12; 0.74) => Var(X)=n x p x (1-p) = 12 x 0,75 x 0,25 but p is 0.74 and not 0.75. Could it be that 9/12=0.75 and the mistake is the first at X~Bi(n;p) where p = 0,74? The mistake goes through the follwing calculation to the end of the solution.
 Henock A. 0 0 done
 Juliet N. 0 0 not clear
 Juliet N. 0 0 Mean and variance of a binomial random variable
 Rachel N. 0 0 The mean and variance of a binomial random variable
 Jahidul I. 0 0 Mean and Variance of Binomial Random Variables The probability function for a binomial random variable is b ( x ; n,p ) =
 Jahidul I. 0 0 what is the Binomial Random Variables ?
 Selman R. 0 0 Mean = p; variance = p*q
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