Loi sur les exemples de Questions partie 2
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Mathématiques de la Loi sur l'examen partie 2

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# Loi sur les exemples de Questions partie 2

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• Notes d'étude
• Révisions du sujet
 Petra S. 0 0 I never knew how to do ratio between a circle and a square. Helpful to now know the formula. One side of square is x and r is the radius of the circle. Formula to get r squared is x/2 squared plus x/2 squared. Figure out r. Square area equals length times width and circle equals Pi times r squared. Divide area of square by area of circle and the answer is 2/Pi.
 Jorge Carlos V. 0 0 There is a simpler solution: The square is two triangles with base 2r and height r, that is 2*squared(r). The area of circle is pi*squared(r).The requested ratio is the square area divided by the circle area, that is: 2/pi
 Khalid B. 1 0 5/2π
 Khalid B. 0 0 3
 Khalid B. 0 0 1
 Khalid B. 0 0 0.25
 Khalid B. 0 0 0.50
 Linda E. 0 0 It was very helpful
 Candance S. 0 0 I guess I was the only one who was lost by that whole equation
 Hafid A. 0 0 G